From: Ramakrishnan Muthukrishnan <vu3rdd@gmail.com>
Date: Sat, 2 Apr 2011 07:42:16 +0000 (+0530)
Subject: mid air commit to solution 3.31
X-Git-Url: https://git.rkrishnan.org/pf/content/en/seg/%22news.html/(%5B%5E?a=commitdiff_plain;h=87b295369de0d53abee6c9cd6ad4a5546ffaf490;p=sicp.git

mid air commit to solution 3.31
---

diff --git a/src/sicp/ex3_31.rkt b/src/sicp/ex3_31.rkt
new file mode 100644
index 0000000..4b78357
--- /dev/null
+++ b/src/sicp/ex3_31.rkt
@@ -0,0 +1,32 @@
+#lang racket
+
+#|
+
+If we don't call the proc in the add-action! procedure then the outputs for the 
+given inputs will be in some undefined default states. They won't reflect the 
+logic that the function blocks are representing.
+
+Let us take half adder example:
+
+(define (half-adder a b s c)
+  (let ((d (make-wire)) (e (make-wire)))
+    (or-gate a b d)
+    (and-gate a b c)
+    (inverter c e)
+    (and-gate d e s)
+    'ok))
+
+If accept-action-proc! is defined without the call to proc, i.e.
+
+(define (accept-action-proc! proc)
+  (set! action-procedures (cons proc action-procedures))
+
+then, let us see what happens.
+
+The or-gate definition will call add-action on both its inputs a and b. make-wire 
+by default sets the wire value as 0. So, for the default case, the inputs to the
+half-adder will be 0 and 0 and the output of the or-gate and and-gate will be 0.
+i.e. D = 0, C = 0.
+E will also be 0. So, S = 0 C = 0, irrespective of the initial values of a and b.
+
+|# 
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