#lang racket

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Only the below three cases will remain:

101: 	P1 sets x to 100 and then P2 increments x to 101.
121: 	P2 increments x to 11 and then P1 sets x to x times x (121).
100: 	P1 accesses x (twice), then P2 sets x to 11, then P1 sets x.

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